Find the absolute maximum and minimum values of the function f(x)=2x^3-15x^2+36x. On the interval [1, 5] and determine where these values occur
f”(x) = 6x^2 – 30x +36
solve f”(x) = 0
you get x = 2 and 3
Therefore, your ABSOLUTE max or min will be either at x=1,2,3,5, note you are solving for absoulte max or min not local min or max
Simply, solve f(1), f(2), f(3),f(5). You should be able to solve this if your in calculus lol
the biggest number will be your absolute max and the smallest will be absoulte min within that domain.